We'll need to dust off the Combined Gas Law to figure this one out. That's the physical law that says gas temperature, pressure, and volume are all related. Pressure and temperature are directly proportional--As temperature goes up, pressure goes up proportionally and vice versa. Pressure and volume are inversely proportional--as volume expands, pressure decreases and vice versa. And so it follows that volume and temperature must also be directly proportional. Put mathematically, we can say that for a given mass of air, the ratio of product of the pressure and volume and the temperature must remain constant.

PV/T = k (where k is a fixed constant)

If we change any one of those variables, we can solve for the others. Because k=k, we can write:

P_{1}*V_{1}/T1 = P_{2}*V_{2}/T_{2}

It's all coming back now, isn't it? (Aww man, I've got a quiz in English next period and I didn't do the reading. What happened in chapter 7?)

Back to New England. The NFL rules are that the balls must be inflated to between 12.5 and 13.5 psi. The report I just read said that 11 of the 12 balls were under-inflated by 2 psi each. I assume that means they must be about 10.5 psi. Let's say it was 70 deg F indoors. The temperature at kickoff was 51 deg F according to the official NFL record, fairly warm for Foxboro this time of year. One gotcha is that temperature and pressure must be expressed in absolute terms, so we need to translate the temps into the Kelvin scale and the baseline atmospheric pressure to the gauge pressure.

Assuming V

(12.5+14.7) * V_{1} / 294.3 = P_{2} * V_{2} / 283.7

Since V

Any warming that may have occurred during halftime when the balls were re-examined would reduce the effect of temperature, and leave more of the discrepancy unaccounted for. Certainly, a full half of play might deflate the balls, but 11 of the 12 were under-pressurized, so I doubt that would explain it. Some balls would be affected much more than others depending on what kind of abuse they get.

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